Question
A train was moving at 60 km/hr for ‘x’ hours. It then
increased its speed by 10 km/hr and travelled for (x + 4) hours. If it covered 910 km in the second stretch, find how much distance it covered initially.Solution
ATQ,
70 × (x + 4) = 910
Or, x + 4 = 13
Or, x = 9
Therefore, required distance = 60 × 9 = 540 km
Two numbers are in the ratio 3:5 and their HCF is 20. Their LCM is
Two numbers are in the ratio 3:7. The product of their H.C.F. and L.C.M. is 2541. The sum of the numbers is:
The HCF of two numbers is 21. Which of the following can never be their LCM?
Find the HCF of 240, 280 and 560.
- If the product of two numbers is 225 and their HCF is 15, then find the LCM of the given two numbers.
The L.C.M of a² – 2a – 3 and a³ + a² + a + 1 is
The H.C.F. of two numbers is 16 and the other two factors of their L.C.M. are 4 and 13. The larger of the two numbers is:
Find the HCF of two numbers if LCM and product of those two numbers are 15 and 675 respectively.
A, B and C start running at the same time and at the same point in the same direction in a circular stadium. A completes a round in 720 seconds, B in 10...
Find the HCF and LCM of 18 and 30.
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