Question
Maya has to go to the airport. If she drives at 36 km/h,
she arrives 1.5 hours late. If she drives at 60 km/h, she reaches 45 minutes early. What is the distance between her house and the airport?Solution
ATQ,
Let the distance = 'd' km
Let the usual time = 't' hours
Then, (d/36) = t + 1.5
Or, t = (d/36) - 1.5
And, (d/60) = t - 0.75
Or, t = (d/60) + 0.75
So, (d/36) - 1.5 = (d/60) + 0.75
Or, (d/36) - (d/60) = 2.25
LCM of 36 and 60 = 180
Or, (5d - 3d)/180 = 2.25
Or, 2d = 405
So, d = 202.5
Therefore, the distance = 202.5 km
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