Question
A man travels 400 km, partly by bike and partly by train.
If the speed of bike is 50 km/h and the speed of train is 100 km/h, and he covers 40% of the distance by bike, what is the average speed of the whole journey? (Round off to nearest integer)Solution
ATQ,
Time taken by bike = [(0.40 × 400)/50] = (160/50) = 3.2 hours
Time taken by train = [(0.60 × 400)/100] = (240/100) = 2.4 hours
Average speed = [(Total distance)/(Total time)] = [400/(3.2 + 2.4)] = (400/5.6) ~ 71 km/h
Rate of change of momentum is -
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