Question
If 'P' reduces his speed by 40% of his original speed,
he arrives at his destination 3 hours later than usual. How much time would he take to reach his destination if he traveled at his original speed?Solution
ATQ,
Let the actual speed of Rahul be ‘s’ km/hr. And, actual time taken by him to reach his destination is ‘t’ hours. So, total distance covered by Rahul in ‘t’ hours = {s × t} km---------- (1) Also, Distance covered by Rahul while travelling at 40% less speed = 60% of s × (t + 3) = 0.6 × s × (t + 3) km ----------- (2) From equation (1) and (2), we have s × t = (3/5) × s × (t + 3) Or, 5st = 3st + 9s Or, 2st = 9s So, t = 4.5 So, required time = 4.5 hours
What will come in place of (?) question mark in the given number series.
960, 960, 480, ?, 40, 8
580 557 528 497 ? 419
- What will come in place of (?), in the given number series.
1, 1, 2, 3, 5, ?, 13 23 40 67 104 ? 208
...1, 7, 25, 61, ?
6, 7, 16, 51, 208, ?
24, 35, 57, 90, 134, ?
21, 28, 39, 52, ?, 88
230 192 172 ? 122 100
...4, 4, 12, 60, ?, 3780
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