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    Question

    If 'P' reduces his speed by 40% of his original speed,

    he arrives at his destination 3 hours later than usual. How much time would he take to reach his destination if he traveled at his original speed?
    A 6.5 hours Correct Answer Incorrect Answer
    B 7.5 hours Correct Answer Incorrect Answer
    C 4.5 hours Correct Answer Incorrect Answer
    D 2.5 hours Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the actual speed of Rahul be ‘s’ km/hr. And, actual time taken by him to reach his destination is ‘t’ hours. So, total distance covered by Rahul in ‘t’ hours = {s × t} km---------- (1) Also, Distance covered by Rahul while travelling at 40% less speed = 60% of s × (t + 3) = 0.6 × s × (t + 3) km ----------- (2) From equation (1) and (2), we have s × t = (3/5) × s × (t + 3) Or, 5st = 3st + 9s Or, 2st = 9s So, t = 4.5 So, required time = 4.5 hours

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