Question
Two motorcycles, a Honda and a Hero, set off
simultaneously from the same location, aiming for the same endpoint. The Honda travels at a speed of 48 km/h, while the Hero moves at 60 km/h. Given that the Hero arrives 20 minutes earlier than the Honda, what is the entire length of the trip?Solution
ATQ, Let the total distance covered be 'a' km So, (a/48) - (20/60) = (a/60) Or, {(a - 16) /48} = (a/60) Or, 5 × (a - 16) = 4a Or, a = 80 So, total distance covered = 80 km
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