Question
A journey of 420 km is completed partly on foot and partly
by bicycle. Walking speed is 6 km/h and biking speed is 21 km/h. If 25% of the distance is walked, what is the average speed of the journey (nearest whole number)?Solution
ATQ,
Time taken on foot = [(0.25 Γ 420)/6] = (105/6) = 17.5 hours
Time taken by bicycle = [(0.75 Γ 420)/21] = (315/21) = 15 hours
Average speed = [(Total distance)/(Total time)] = [420/(17.5 + 15)] = (420/32.5) ~ 13 km/h
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