Question
If a person walks 20% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 459 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 120% of x = 6x/5 km/hr Distance = 459 km According to the question 459/x – 459/(6x/5) = 90/60 459 x [(6 – 5)/6x] = 3/2 Therefore, x = 459 x (1/6) x (2/3) = 51 km/hr
For project appraisal, Net Present Value (NPV) of a project is positive. That implies:
According to Walter’s Model, a firm with high return on investment (RoI) and low cost of capital should:
Consider the following journal entry:
In what circums...
Salaries of ₹1 lakh paid in April 2024 relate to March 2024. As per matching concept, when should this expense be recorded?
As per IRDAI norms, an insurer must maintain a solvency ratio of at least 150%. If an insurer’s available solvency margin is ₹900 crore, what should...
Financial management is generally concerned with the procurement, allocation and control of financial resources of a concern. Its objectives can be:
...Which of the following is not a type of buyer on the GeM?
A Public Cloud is characterized by:Â
For demand drafts, pay orders, or banker’s cheques of ₹50,000 and above, which requirement must be fulfilled as per banking guidelines?
Virat Ltd. issues 5,000 10% preference shares of ₹100 each at ₹96 each. The company proposes to redeem the preference shares at the end of the 10th ...
Relevant for Exams:
