Question
A bus travels from point A to point B at a speed of 48 km/h
and makes the return trip from B to A at a speed of 56 km/h. If the total time taken for the round trip is 39 hours, what is the distance between points A and B?Solution
Let the distance between βAβ and βBβ be βxβ km
According to the question,
(x/48) + (x/56) = 39
Or, (7x + 6x)/336 = 39
Or, 13x = 336 Γ 39
Or, x = 1008
Therefore, distance between βAβ and βBβ = 1008 km
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