Question
How far will 'Puneet' travel by the time he catches up to
'Bittu', given that 'Puneet' starts 90 km behind and moves at 45 km/h while 'Bittu' moves at 30 km/h?Solution
ATQ,
Relative speed of 'Puneet' w.r.t 'Bittu' = 45 - 30 = 15 km/h
Time taken by 'Puneet' to overtake 'Bittu' = (90/15) = 6 hours
So, distance covered by 'Puneet' in 6 hours = 45 X 6 = 270 km
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