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ATQ, Speed of Raj = (1,500/25) = 60 km/h Speed of Suresh = (1,500/20) = 75 km/h Distance covered by Raj in 2 hours (from 2:00 PM to 4:00 PM) = 60 X 2 = 120 km Relative speed of Suresh w.r.t. that of Raj = 75 - 60 = 15 km/h Time taken by them to meet each other = (120/15) = 8 hours So, required time = 4:00 PM + 8 hours = 12:00 AM Required distance = 75 X 8 = 600 km
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