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ATQ, Speed of Karan = (2,400/40) = 60 km/h Speed of Mohit = (2,400/32) = 75 km/h Distance covered by Karan in 2 hours (from 7:00 AM to 9:00 AM) = 60 X 2 = 120 km Relative speed of Mohit w.r.t. that of Karan = 75 - 60 = 15 km/h Time taken by them to meet each other = (120/15) = 8 hours So, required time = 9:00 AM + 8 hours = 5:00 PM Required distance = 75 X 8 = 600 km
123% of 3825 +2745 =11800 - ?
...? = (7.11/2.12) + (10.88/4.09) + (45.12/11.98)
(239.89 ÷ 3.89) – (144.01 ÷ 5.73) = ?2
2660.03 ÷ 69.98 x 49.9 = ? + 10.32
If 'a' = √1024 ÷ 4 + 96 ÷ 3 + 85 ÷ 17 and 'b' = 30 × 18 ÷ 6 - 7² + 110, then find the value of (a + b).
...233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99
? = 22.08 + 13.99 × 22.07
? × 32.91 – 847.95 ÷ √16.4 – 13.982 = √24.7 × 24.04
30.05% of 360.05 – 25.15% of 99.99 × 3.02 = ?