Question
Virat typically covers the journey from Point 'P' to
Point 'Q' at a speed of 24 km/h. However, on a particular day, he traveled 40% of the total distance at a speed that was 125% of his usual speed and the remaining 60% at 75% of his usual speed. As a result, his total travel time increased by 1.5 hours compared to the usual time. Determine the total distance between Point 'P' and 'Q'.Solution
Let the distance between Point 'P' and 'Q' be = '10x km According to the question, {(10x X 0.40) ÷ (1.25 X 24)} + {(10x X 0.60) ÷ (0.75 X 24)} - (10x ÷ 24) = 1.5 Or, (4x/30) + (6x/18) - (10x/24) = 1.5 Or, (0.8x + 2x - 2.5x) ÷ 6 = 1.5 Or, 0.3x = 9 So, x = 9 ÷ 0.3 = 30 So, total distance travelled by Virat = 10 X 30 = 300 kmÂ
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