Question
500 metres long train crosses a man who is moving in the
same direction with a certain speed, in 50 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 500/20 = 25 m/sec Let the speed of the man be ‘s’ m/sec Relative speed of the train = (25 – s) m/sec According to the question, (25 – s) = 500/50 Or, s = 25 – 10 = 15 Therefore, speed of the man = 15 m/sec
Statement: M=N<Q ≤P ≥R;Q<T;U<S>T
Conclusions:
1. U > Q
2. N > R
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