Question
500 metres long train crosses a man who is moving in the
same direction with a certain speed, in 50 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 500/20 = 25 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (25 β s) m/sec According to the question, (25 β s) = 500/50 Or, s = 25 β 10 = 15 Therefore, speed of the man = 15 m/sec
{(522Β β 482Β ) Γ· (27 + 73)} Γ 35 = ?% of 175
(512) (2/3) Γ β64 Γ· (512) (1/3) = (64) (?/2) Γ· (2)6Β
β324 + β484 + 63 = ?2Β
20.05% of 220.05 β 15.15% of 99.99 Γ 2.02 = ?
- What will come in the place of question mark (?) in the given expression?
(β1089 + 47) X 4.5 = ? - β256 X 10 - What will come in the place of question mark (?) in the given expression?
(120 - ?) Γ· 2 + 35 = 86 - 11 What will come in the place of question mark (?) in the given expression?
[{(24) 2 Γ· (6) 2 } Γ· 8]4 = ? Γ· 5
95% of 830 - ? % of 2770 = 650
(22 + β3364)/(? + 4) = 10
