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      Question

      The train service was disrupted due to an accident after

      a travel of 30 km. The speed was reduced to four-fifths of the original speed. This caused a delay of 45 min. If the accident had happened 20 km farther, it would have been running late for 36 min. What was the original speed of the train?
      A 40 km/h Correct Answer Incorrect Answer
      B 60 km/h Correct Answer Incorrect Answer
      C 48.5km/h Correct Answer Incorrect Answer
      D 33.3 km/h Correct Answer Incorrect Answer

      Solution

      Let the speed of the train be x. We know that. ⇒ Speed = Distance/Time Speed after accident = 4/5 of x = 4x/5 According to the question, The time difference in covering 20 km due to change in speed = 45 - 36 = 9 min 20/(4x/5) -(20/x) =9/60 100/4x)-20/x=9/60 ⇒ x = 33.33 km/h ∴ The original speed of the train is 33.33 Km/h.

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