Question
Determine the distance covered by the dog in 2 hours and
30 minutes if the dog's speed is 15 km/h faster than the cow's. The time it takes for the cow to cover 210 km is 3 hours less than the time it takes for the dog to cover 450 km.Solution
We can say that the speed of cow is ‘a’ km/h Speed of dog = (a + 15) km/h According to question; 450/(a + 15) – 210/a = 3 150/(a + 15) – 70/a = 1 150x – 70(a + 15) = a(a + 15) 150a – 70a – 1050 = a2 + 15a a2 – 65a + 1050 = 0 Solving above equation we get a = 35, 30 So, speed of bus will be either 50 km/h or 45 km/h So distance cannot be determined
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 × (484 ÷ 44) + 450 ÷ 9 = ?
40 × 5 + 27) × 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
√1296 + (2/3 of 45% of 480) = ?
- Determine the value of ‘p’ if p = √529 + √1444
120% of 250 + 110 + 135 ÷ 5 = ?
