Question
Robert started his journey on Monday and travelled at
constant speed. Next day by 10.30 am, he had covered 4/7 of his whole journey and on the same day by 4 pm, he had covered 5/6 of his whole journey. He started his journey atSolution
Let the total journey be = 42 km (LCM of the denominator of 4/7, 5/6) At 10.30 am, Robert covers 4/7 of the whole journey i.e., 42 × 4/7 = 24 km At 4.00 pm, Robert covers 5/6 of the whole journey i.e., 42 × 5/6 = 35 km Therefore, Robert covers (35 - 24) = 11 km in (4.00 pm – 10.30am) = 5.5 hours. Then the speed of a Robert = 11/(5.5 ) = 2 km per hour Time taken by Robert to cover 24 km = 24/2 hours =12 hours Then the starting time of the journey is 10.30am - 12 hours = 10:30 pm
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