Question
A man walks from town A to town B at 5 km/h and returns from B to A along the same route at 3 km/h. If the total time taken for the round trip is 3 hours 12 minutes, what is the distance between A and B?
Solution
ATQ, Let distance one way = d km. Time AβB at 5 km/h = d/5 hours Time BβA at 3 km/h = d/3 hours Total time = d/5 + d/3. Given total time = 3 hours 12 minutes = 3 + 12/60 = 3.2 hours. So: d/5 + d/3 = 3.2 LCM of 5 and 3 = 15: (3d + 5d) / 15 = 3.2 8d / 15 = 3.2 d = 3.2 Γ 15 / 8 = (3.2 / 8) Γ 15 = 0.4 Γ 15 = 6 km.
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