Question

Three persons named P, Q, R started their journey at 9.30 AM, 11.30 AM, 2 PM respectively from A to
B. The speed of Q is √625 m/sec. Q reached the destination at 7.30 pm on the same day. Q is fastest & R is not the slowest. The speed of P is 20% less than the speed of Q, then in what time P will reach the destination?
i. 6 hours more than Q
ii. P will reach B at 7.30 pm
iii. The total reaching time of P and Q is 18 hrs

Q: Answer-Three persons named P, Q, R started their journey at 9.30 AM, 11.30 AM, 2 PM respectively from A to...

Speed of Q 625 msec 25 msec 25 x 185 90 kmhr Time taken to reach point B by Q 8 hrs 11.30 am 730 pm Distance between A and B 90 x 8 720 km Speed of P 0.8 x 90 72 kmhr Now, From i Time taken by P to cover the distance 72072 10 hrs Difference of time is 2 hrs, so i is not true. From ii P started journey at 930 AM, so he will reach by 730 pm 10 hrs So , ii is true. From iii Total time 8 10 18 hrs iii is true.