Question
Three persons named P, Q, R started their journey at
9.30 AM, 11.30 AM, 2 PM respectively from A to B. The speed of Q is √625 m/sec. Q reached the destination at 7.30 pm on the same day. Q is fastest & R is not the slowest. The speed of P is 20% less than the speed of Q, then in what time P will reach the destination? i. 6 hours more than Q ii. P will reach B at 7.30 pm iii. The total reaching time of P and Q is 18 hrsSolution
Speed of Q = √625 m/sec = 25 m/sec = 25 x 18/5 = 90 km/hr Time taken to reach point B by Q = 8 hrs (11.30 am – 7:30 pm) Distance between A and B = 90 x 8 = 720 km Speed of P = 0.8 x 90 = 72 km/hr Now, From i: Time taken by P to cover the distance = 720/72 = 10 hrs Difference of time is 2 hrs, so i is not true. From ii: P started journey at 9:30 AM, so he will reach by 7:30 pm (10 hrs) So , ii is true. From iii: Total time =  8 + 10 = 18 hrs iii is true.
√? + √626 × 13.998 - 6.02 × 2.97 = 345.995Â
79.79% of 299.87 - 54.67% of (39.982 - 9.822 ) = ? - 19.92 × 199.98
1560.182 ÷ √168 + √143 * √224 – 4649.87 ÷ 30.883= ?    Â
(9/20 of 3998.93) - √2499.57 + (17.87% of 1199.67) = ?
Find the approximate value of the given expression and choose the nearest option.
√784.1 + 29.9% of 450.2 − 149.7 ≈ ?
456 x 99.999 + 654 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will replace the question mark (?) in the following?
? = 2...
What approximate value should replace the question mark?
1 ÷ 9.08 of 242.60 + 40.10% of 200 = ?² - 61.92
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