New RBI Grade B 2024 Batch 7 45+ 20 Days Study Plan; Download Now !!!
Register

Question

Three persons named P, Q, R started their journey at 9.30 AM, 11.30 AM, 2 PM respectively from A to B. The speed of Q is √625 m/sec. Q reached the destination at 7.30 pm on the same day. Q is fastest & R is not the slowest.

The speed of P is 20% less than the speed of Q, then in what time P will reach the destination?

i. 6 hours more than Q

ii. P will reach B at 7.30 pm

iii. The total reaching time of P and Q is 18 hrs

A Only i Correct Answer Incorrect Answer
B Only ii Correct Answer Incorrect Answer
C Only ii and iii Correct Answer Incorrect Answer
D All i, ii and iii Correct Answer Incorrect Answer
E None of these Correct Answer Incorrect Answer

Solution

Speed of Q = √625 m/sec = 25 m/sec = 25 x 18/5 = 90 km/hr Time taken to reach point B by Q = 8 hrs (11.30 am – 7:30 pm) Distance between A and B = 90 x 8 = 720 km Speed of P = 0.8 x 90 = 72 km/hr Now, From i: Time taken by P to cover the distance = 720/72 = 10 hrs Difference of time is 2 hrs, so i is not true. From ii: P started journey at 9:30 AM, so he will reach by 7:30 pm (10 hrs) So , ii is true. From iii: Total time  =  8 + 10 = 18 hrs iii is true.

Practice Next
×
×