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      Question

      Ajay and Vishal left the place ‘X’ with different

      speeds which are in the ratio 9:4 respectively. Ajay left the place 30 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 40 meters apart from Vishal, then find the speed of Vishal.
      A 16 km/hr Correct Answer Incorrect Answer
      B 32 km/hr Correct Answer Incorrect Answer
      C 25 km/hr Correct Answer Incorrect Answer
      D 20 km/hr Correct Answer Incorrect Answer
      E 18 km/hr Correct Answer Incorrect Answer

      Solution

      Let the speeds of Ajay and Vishal be 9x and 4x km/hr respectively. Distance covered by Vishal in 72 seconds = 4x x (5/18) x 72 = 80x m Distance covered by Ajay in 30 seconds = 9x x (5/18) x 30 = 75x m According to the question, => 80x – 75x = 40 => x = 8 Therefore, the speed of Vishal = 4x = 32 km/hr

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