Question
A thief is spotted by a policeman from a distance of 200
meters. When the policeman starts the chase, the thief also starts running. If the speed of the thief is 10 km/h and that of the policeman is 12 km/h, how far would the thief have run before he is overtaken?Solution
ATQ, Relative speed = 12 - 10 = 2 km/h. Distance gap = 200 m = 0.2 km. Time taken to catch = Distance / Relative Speed = 0.2 / 2 = 0.1 hours. Distance covered by thief = Speed of thief × Time = 10 × 0.1 = 1 km.
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