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ATQ, Let the usual time taken by the person be 'T' hours. Using, distance = speed × time We have, 'D' = 5T ----------- (I) And, 'D' = 6 × {T - (10/60)} -------- (II) From equation (I) and (II), We have, 5T = 6 × {T - (10/60)} Or, 5T = 6T - 6 × (10/60) Or, T = 1 On putting the value of 'T' = 1 in equation (I), We have 'D' = 5 × 1 = 5 km So, the required time = (2 × 5) ÷ 8 = (10/8) = 1.25 hours
√2703.88 × √784.15 – 26² = ? - (34.85)²
√92.10 + √256.30 + 60.78% of (420.90 + 19.36% of 140.25) = ?
25.09 × (√15 + 19.83) = ? of 19.87 ÷ 4.03
Direction: Please solve the following expression and choose the closest option
52.08% of 645.92 + 1840% of 47.96 = ?
19.99% of 79.98 = ?2– 159.99% of 12.5
19.97% of 3/5 ÷ (1 ÷ 74.99) = ?
30.22% of (61.9 × 5.01) + 69.97 =?
1199.98 ÷ 40.48 × 20.12 = ? × 3.16
88% of 900.23 + 74.99 = ?