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Let length of train A = x Length of platform = 2x Speed = distance/time ⇒ 90 x 5/18 = (x + 2x)/12 ⇒ x = 100 m = length of train A Length of platform = 100 x 2 = 200m For train B, Speed = distance/time ⇒ (200 + 340)/18 x (18/5) ⇒ 108 km/hr
Calculate the maximum and minimum value of (8cosA + 15sinA + 15), if 'q' lies in the first quadrant.
If sinAo = (√3/2), then find the value of (sin245o + cos230o) × A ÷ 5 given that 0 < A < 90...
If Sin 3A = Cos (A - 46°) where 3A is acute angle, then the Value of A is
Simplify: sin (A + B) sin (A - B)
If θ is an acute angle and sin θ + cosec θ = 2, then the value of sin2 θ + cosec2 θ is:
If sec A + tan A = 3 then the value of cot A is:
If tan A = , find the va...
The value of sec2 45˚ + 2 tan 135˚ is –