Question
260 metre long train βAβ can cross a platform of
length 180 metres in 16 seconds. If the speed of train βBβ is 6 m/s more than that of train βAβ, then find the distance travelled by train βBβ in 5 hours.Solution
Speed of train βAβ = {(260 + 180)/16} = (440/16) = 27.5 m/s Speed of train βBβ = 27.5 + 6 = 33.5 m/s = 33.5 Γ (18/5) = 120.6 km/hr Required distance travelled by train βBβ = 120.6 Γ 5 = 603 km
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