Travelling at a speed of 54 km/h, Chaman reaches a place 3 minutes early. If he had travelled at a speed of 48 km/h, he 7 would have been 1 minute late. What is the distance Chaman had to travel?
Let the actual time be t. When Chaman reaches early, ⇒ Speed = 54 km/hr ⇒ Time = (t – 3) min = (t – 3)/60 hr ⇒ Distance = {(t – 3)/60} × 54 = {(9t – 27)/10} km When Chaman reaches late, ⇒ Speed = 48 km/hr ⇒ Time = (t + 1) min = (t + 1)/60 hr ⇒ Distance = {(t + 1)/60} × 48 = {(8t + 8)/10} km Now, we get, ⇒ {(9t – 27)/10} = {(8t + 8)/10} ⇒ t = 35 min Now, ⇒ Distance = {(9t – 27)/10} = 288/10 = 28.8 km
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