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    Question

    Travelling at a speed of 54 km/h, Chaman reaches a place

    3 minutes early. If he had travelled at a speed of 48 km/h, he would have been 1 minute late. What is the distance Chaman had to travel?
    A 25.8 km Correct Answer Incorrect Answer
    B 31.5 km Correct Answer Incorrect Answer
    C 28.0 km Correct Answer Incorrect Answer
    D 28.8 km Correct Answer Incorrect Answer

    Solution

    Let the actual time be t. When Chaman reaches early, β‡’ Speed = 54 km/hr β‡’ Time = (t – 3) min = (t – 3)/60 hr β‡’ Distance = {(t – 3)/60} Γ— 54 = {(9t – 27)/10} km When Chaman reaches late, β‡’ Speed = 48 km/hr β‡’ Time = (t + 1) min = (t + 1)/60 hr β‡’ Distance = {(t + 1)/60} Γ— 48 = {(8t + 8)/10} km Now, we get, β‡’ {(9t – 27)/10} = {(8t + 8)/10} β‡’ t = 35 min Now, β‡’ Distance = {(9t – 27)/10} = 288/10 = 28.8 km

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