Question
Buses A and B are moving around a circular ground of
radius 420 m. If the speeds of the buses A and B are 12 m/sec and 20 m/sec respectively, then what is the difference between the time taken by bus A and B to complete 2 round of the ground?Solution
Circumference if the ground = 2πr = 2 × 22/7 × 420 = 2640 m So, distance = 2640 m Time taken by bus A to cover 2 rounds of a ground = (2640/12) × 2 = 440 Time taken by bus B to cover 2 rounds of a ground = (2640/20) × 2 = 264 Required difference = 440 – 264 = 176
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 11.99 × 24.07
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
11.67 × 50.23 + ? = 14.88% of 600.44 + 9.66 × 8.272
78% of 1450 + 26² = ? + 1323 ÷ 17
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...