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ATQ,
'A' = 81 ÷ 9 × 6 - 27
Or, 'A' = 9 × 6 - 27 = 54 - 27 = 27
'B' = (3/2) × (40/3) + 30 ÷ 6
Or, 'B' = 20 + 5 = 25
'C' = (40 + 12 - 22) ÷ 6 × 5
Or, 'C' = 30 ÷ 6 × 5 = 5 × 5 = 25
'D' = [(8/12) × 36 - 6] ÷ 2 + 4
Or, 'D' = (24 - 6) ÷ 2 + 4
Or, 'D' = 18 ÷ 2 + 4 = 9 + 4 = 13
Therefore, 'B' and 'C' are same.
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