A man invested certain sum at simple interest of r% p.a. such that it amounts to 124% of itself in 10 years. Find the interest earned when Rs. 10000 is invested at simple interest of r% p.a. for 3 years.
Let the sum invested be Rs. ‘P’ Therefore, interest earned in 10 years = 1.24P – P = Rs. 0.24P ATQ; 0.24P = (P × r × 10) ÷ 100 Or, r = 24 ÷ 10 Or, r = 2.4 So, required interest earned = (10000 × 2.4 × 3) ÷ 100 = Rs. 720
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