Question
Train P starts from Lucknow to Dehradun at 11:55 am with
an average speed of 25.5 m/s. Train Q starts from Dehradun to Lucknow at 1:35 pm with an average speed of 20.5 m/s. At what time the two trains will meet each other if the distance between Lucknow and Dehradun is 620 Km.Solution
Speed of train P = 25.5 × 18/5 = 91.8 Km/h Speed of train Q = 20.5 × 18/5 = 73.8 Km/h Distance travelled by train P till 1:35 pm = 91.8 × 5/3 = 153 Km Relative speed of trains = 91.8 + 73.8 = 165.6 Km/h Remaining distance to be travelled after 1:35 pm = 620 – 153 = 467 Km Time taken to cover 467 Km = 467/165.6 = 17/6 = 2 hours 50 minutes So the two trains will meet each other at 1:35 + 2:50 = 4:25 pm
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.) 
- 24.45% of 14.99% of 14999.78 + 159.80 = ?% of 1999.78 
- 15.78% of (287 + 302) + 12³ = ?% of 170 + 8 × 14 + 3² 
- ? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09) 
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.) 
- 1784.04 - 483.98 + 464.98 ÷ 15.06 = ?3 
- ? = 54.89 × 270.08 ÷ 135.17 + 464.35 ÷ 29.03 
- 233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99