Question
On travelling with 45% less speed than his actual speed,
Mohan reached the destination 6 hours late. Find the time taken by him to reach his destination while travelling with his actual speed.Solution
ATQ, Let the actual speed of Mohan be ‘s’ km/hr. And, actual time taken by him to reach his destination is ‘t’ hours. So, total distance covered by Mohan in ‘t’ hours = {s × t} km --------- (1) Also, Distance covered by Mohan while travelling at 45% less speed = 55% of s × (t + 6) = 0.55 × s × (t + 6) km --------- (2) From equation (1) and (2), we have s × t = (11/20) × s × (t + 6) Or, 20st = 11st + 66s Or, 9st = 66s So, t = 66/9 = 7.33 hours So, required time = 7.33 hours
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