Question
In a mixture of 40 liters, the ratio of milk to water is
5:3. How much milk must be replaced by water so that the new ratio becomes 1:1?Solution
Let x liters of milk be replaced by water. Milk in the mixture after replacement = (40 × 5/8) - x = 25 - x. Water in the mixture after replacement = (40 × 3/8) + x = 15 + x. We want the new ratio of milk to water to be 1:1. So, 25 - x = 15 + x. Solving for x: 25 - 15 = 2x 10 = 2x x = 5 liters. Correct answer: a.
I. 2x2 – 5x – 63 = 0
II. 2y2 – 7y – 72 = 0
If x2Â - 3x - 18 = 0 and y2Â + 9y + 18 = 0, which of the following is true?
Solve the given two equations and answer the two questions that follow as per the instructions given below.
I. (1/4) + 7.5p(-2) = 3.62...
I. 2x2 + 3x - 9 = 0
II. 3y2 - y - 10 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 20x + 96 = 0
Equation 2: y² - 18y + 72 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
l. x2 - 16x + 64 = 0
II. y2Â = 64
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
I. 10x² - 11x + 3 = 0
II. 42y² - 23y – 10 = 0
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