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    Question

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    A 6,768 Correct Answer Incorrect Answer
    B 5,640 Correct Answer Incorrect Answer
    C 7,008 Correct Answer Incorrect Answer
    D 6,840 Correct Answer Incorrect Answer

    Solution

    A person divides a certain amount among his three sons in the ratio = 3 тИ╢ 4 тИ╢ 5 Let money get by first, second and third son be 3x, 4x and 5x respectively Total share = 3x + 4x + 5x = 12x Here first son got minimum share i.e 3x If person had divided total amount in the ratio = 1/3 тИ╢ 1/4 тИ╢ 1/5 LCM of 3, 4 and 5 = 60 Ratio of First, second and third = (1/3) × 60 тИ╢ (1/4) × 60 тИ╢ (1/5) × 60 ⇒ 20 тИ╢ 15 тИ╢ 12 Share of first student = (12x/47) × 20 ⇒ 240x/47 According to the question ⇒ (240x/47) – (3x) = 1188 ⇒ (240x – 141x)/47 = 1188 ⇒ 99x/47 = 1188 ⇒ x = 12 × 47 ⇒ x = 564 Total amount = 12x ⇒ 12 × 564 = Rs. 6768 ∴ The total amount is Rs. 6768

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