Question
Three numbers ‘A’, ‘B’ and ‘C’ are such
that ‘A’ is two-third of ‘B’ and ‘C’ is equal to the average of ‘A’ and ‘B’. If the sum of these three numbers is 450, then find the value of ‘A’.Solution
Let the value of ‘B’ be ‘6x’ So, value of ‘A’ = (2/3) × 6x = ‘4x’ So, value of ‘C’ = (4x + 6x)/2 = 10x/2 = ‘5x’ ATQ; 4x + 6x + 5x = 450 Or, 15x = 450 Or, x = 30 So, value of ‘A’ = 4x = 4 × 30 = 120
55 46 60 41 65 36 ?
91   93   97   100   ?   113
12             10            13                18.5                  25.50       �...
80, 255, 624, ?, 2400, 4095
18 Â Â Â Â 32 Â Â Â 50 Â Â Â 72 Â Â Â Â 98 Â Â Â Â ?
100Â Â Â Â 221Â Â Â Â 77Â Â Â Â 245Â Â Â Â 50Â Â Â 275
Three series are provided below. You need to determine the values of A, B, and C and subsequently establish a relationship among them.
I: 4, 10...
32, 8, 4, ?, 3, 3.75
30    32    67    206    ?     4166
18Â Â Â Â Â Â Â Â Â Â 434Â Â Â Â Â Â Â Â 642Â Â Â Â Â Â Â Â 746Â Â Â Â Â Â Â Â 798Â Â Â Â Â Â Â Â ?
...