Question
Three numbers βAβ, βBβ and βCβ are such
that βAβ is two-third of βBβ and βCβ is equal to the average of βAβ and βBβ. If the sum of these three numbers is 450, then find the value of βAβ.Solution
Let the value of βBβ be β6xβ So, value of βAβ = (2/3) Γ 6x = β4xβ So, value of βCβ = (4x + 6x)/2 = 10x/2 = β5xβ ATQ; 4x + 6x + 5x = 450 Or, 15x = 450 Or, x = 30 So, value of βAβ = 4x = 4 Γ 30 = 120
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