Question
A box contains the coins of 5p, 10p and 25p are in the
ratio 3:4:6. If there is Rs. 82 in all, how many 10p coins are there?Solution
Let the no. of 5p, 10p, 25 p coins be 3x, 4x & 6x respectively. Then sum of their values = Rs. [{5 x (3x/100) + 10 x (4x /100) + 25 x (6x/100)}] =Rs. [(15x/100) + (40x /100) + (150x/100)] =Rs. (15x + 40x + 150x/100) = Rs. (205x /100) Therefore, 205x /100 = 82 x = 82 x (100/205) x = 40 Hence the no. of 10p coins = 4x = 4 x 40 = 160
14.99% of 7820 + 5535.25 ÷ 123.001 - ? = 84
18.22 × 11.99 + 154.15 = ?
 (3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
5.25 x 4.09 + 3.99 x 9.67 + 6.01 x 14.88 = ?
? = 16.08 + 13.99 × 25.07
20.99 × √4.09 × 30.09 = ? × √195.99 × 15.09
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
30.01 × √1023 + 196 = ? 2 – 287
?% of (150.31 ÷ 14.97 × 50.011) = 319.98