Question
A container holds a mixture of juice and water in the ratio of 5:2. When 6 liters of juice are added to the mixture, the ratio of juice to water changes to 3:1. How much mixture was originally in the container?
Solution
ATQ, Let, initial amount of juice and water in the container be ‘5x’ litres and ‘2x’ litres respectively. So, (5x + 6)/2x = 3/1 5x + 6 = 6x x = 6 Required amount of mixture = 7x = 42 litres
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