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ATQ; Speed of 'P' = (5/18)×18 = 5 m/s Time taken by P to cover 500 metres = 500/5 = 100 sec's Distance travelled by Q = (500 - 25) = 475 metres Time taken by Q to cover 475 metres = (100 - 5) = 95 seconds So, speed of Q = 475/95 = 5 m/s
I. p²= ∛1331
II. 2q² - 21q + 55 = 0
Equation 1: x² - 120x + 3500 = 0
Equation 2: y² - 110y + 3025 = 0
I: 2x² - 8x + 6 = 0
II: 3y² - 12y + 9 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
Quantity I: A vessel contains a mixture of milk and water in the ratio of 7 : 5. If 9 litre of mixture is sold and replaced by same amount of water then...
Find the value of 'x' and 'y' in the following equation:
8x - 3y = 58
5x + 2y = 106
Solve both equations I & II and form a new equation III in variable ‘r’ (reduce to lowest possible factor) using roots of equation I and II as per ...
