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ATQ,
From I:
20x² – 43x + 21 = 0
20x² – 15x – 28x + 21 = 0
5x(4x – 3) – 7(4x – 3) = 0
(5x – 7)(4x – 3) = 0
x = 7/5, 3/4
x = 1.4, 0.75
From II:
5y² – 17y + 14 = 0
5y² – 10y – 7y + 14 = 0
5y(y – 2) – 7(y – 2) = 0
(5y – 7)(y – 2) = 0
y = 7/5, 2.
Y = 1.4, 2
So x ≤ y
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