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    Question

    I. 12y2 + 11y – 15 = 0 II.

    8x2 – 6x – 5 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x ≥ y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 12y2 + 11y – 15 = 0 12y2 – 9 y + 20y – 15 = 0 3 y(4 y – 3) + 5(4 y – 3) = 0 (3 y + 5) (4 y – 3) = 0 y = 3/4, -5/3 II. 8x2 – 6x – 5 = 0 8x2 – 10x + 4x – 5 = 0 2x(4x – 5) + 1(4x – 5) = 0 (4x – 5) (2 x+1) = 0 x = 5/4, -1/2 Hence, relationship cannot be established between x and y

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