Question
Given the product of the roots of the equation is
z2 - (b+c)z + (c+61) = 0 is 63 and sum of roots is 16. Find the value of 2b+3c?Solution
ATQ, So, (c + 61) = 63 Or, c = 2 (b + c) = 16 Or, b = 16 - 2 = 14 So, 2×14 + 3×2 = 34
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