Question
I. 6x2 + 23x + 10 = 0 II.
2y2 - 3y - 5 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 6x2Â + 23x + 10 = 0 => 6x2Â + 20x + 3x + 10 = 0 => 2x(3x + 10) + 1(3x + 10) = 0 => (2x + 1) (3x + 10) = 0 => x = -1/2, -10/3 II. 2y2Â - 3y - 5 = 0 => 2y2Â - 5y + 2y - 5 = 0 => y(2y - 5) + 1(2y - 5) = 0 => (y + 1) (2y - 5) = 0 => y = -1, 5/2 Hence, x = y or the relationship cannot be established.
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