Question

    I. x2 + 25x + 154 = 0 II.

    y2 + 27y + 181 = 0 In the following questions, two equations numbered I and II are given.  You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x < y Correct Answer Incorrect Answer
    C If x ≥ y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E If x = y or Relationship between x & y cannot be established Correct Answer Incorrect Answer

    Solution

    I. x2 + 25x + 154 = 0 => x2 + 14x + 11x + 154 = 0 => x(x + 14) + 11(x + 14) = 0 => (x + 11) (x + 14) = 0 => x = -11, -14 II. y2 + 27y + 181 = 0 On solving my qudratic equation formlula we get:-  x = (- b ± √(b2 - 4ac)) /2a. Hence, x = y or the relationship cannot be established.

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