Question
I. x2 + 25x + 154 = 0 II.
y2 + 27y + 181 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. x2 + 25x + 154 = 0 => x2 + 14x + 11x + 154 = 0 => x(x + 14) + 11(x + 14) = 0 => (x + 11) (x + 14) = 0 => x = -11, -14 II. y2 + 27y + 181 = 0 On solving my qudratic equation formlula we get:- x = (- b ± √(b2 - 4ac)) /2a. 
Hence, x = y or the relationship cannot be established.
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