📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      I. 2 x ² - (4 +

      √13) x + 2√13 = 0 II. 10 y ² - (18 + 5√13) y + 9√13 = 0 Directions (Q.21-25): In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer
      A If x ≥y Correct Answer Incorrect Answer
      B If x ≤y Correct Answer Incorrect Answer
      C If x>y Correct Answer Incorrect Answer
      D If x Correct Answer Incorrect Answer
      E If x=y or relationship between between x and y cannot be established Correct Answer Incorrect Answer

      Solution

      I. 2 x ² - (4 + √13) x [if gte msEquation 12]>x [if !msEquation]--> [endif]--> + 2√13 = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> 2 x ² - 4 x - √13x + 2√13 = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> 2 x ( [if gte msEquation 12]>x [if !msEquation]--> [endif]--> x – 2) - √13 ( [if gte msEquation 12]>x [if !msEquation]--> [endif]--> x– 2) = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> ( [if gte msEquation 12]>x [if !msEquation]--> x-2) (2 x - √13) = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> x = 2, `(sqrt(13))/(2)` [if gte msEquation 12]> √13 2 [if !msEquation]--> [endif]--> II. 10 y ² - (18 + 5√13) y [if gte msEquation 12]>y [if !msEquation]--> [endif]--> + 9√13 = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> 10 y ² - 18 y - 5√13 y + 9√13 = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> 2 y (5 y – 9) - √13 (5 y – 9) = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> (2 y – √13) (5 y – 9) = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> y = `(sqrt(13))/(2)` [if gte msEquation 12]> √13 2 [if !msEquation]--> [endif]--> , `(9)/(5)` [if gte msEquation 12]> 9 5 [if !msEquation]--> [endif]--> Hence, x [if gte msEquation 12]>x [if !msEquation]--> [endif]--> ≥ y [if gte msEquation 12]>y [if !msEquation]--> [endif]-->

      Practice Next
      More Quadratic equation Questions

      Relevant for Exams:

      ask-question