Directions (Q.21-25): In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer
I. 2 x ² - (4 + √13) x + 2√13 = 0
II. 10 y ² - (18 + 5√13) y + 9√13 = 0
AIf x ≥yCorrect AnswerIncorrect Answer
BIf x ≤yCorrect AnswerIncorrect Answer
CIf x>yCorrect AnswerIncorrect Answer
DIf xCorrect AnswerIncorrect Answer
EIf x=y or relationship between between x and y cannot be establishedCorrect AnswerIncorrect Answer
Solution
I. 2 x ² - (4 + √13) x [if gte msEquation 12]>x[if !msEquation]--> [endif]-->+ 2√13 = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]-->2 x ² - 4 x - √13x + 2√13 = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]-->2 x ( [if gte msEquation 12]>x[if !msEquation]--> [endif]-->x – 2) - √13 ( [if gte msEquation 12]>x[if !msEquation]--> [endif]-->x– 2) = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]-->( [if gte msEquation 12]>x[if !msEquation]--> x-2) (2 x - √13) = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]--> x = 2, `(sqrt(13))/(2)` [if gte msEquation 12]>√132[if !msEquation]--> [endif]-->II. 10 y ² - (18 + 5√13) y [if gte msEquation 12]>y[if !msEquation]--> [endif]-->+ 9√13 = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]-->10 y ² - 18 y - 5√13 y + 9√13 = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]-->2 y (5 y – 9) - √13 (5 y – 9) = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]-->(2 y – √13) (5 y – 9) = 0 [if gte msEquation 12]>⇒[if !msEquation]--> [endif]--> y = `(sqrt(13))/(2)` [if gte msEquation 12]>√132[if !msEquation]--> [endif]-->,`(9)/(5)` [if gte msEquation 12]>95[if !msEquation]--> [endif]--> Hence, x [if gte msEquation 12]>x[if !msEquation]--> [endif]-->≥ y [if gte msEquation 12]>y[if !msEquation]--> [endif]-->