Question
The time taken by a boat to
travel 'd' kilometers downstream is 8 hours, while the time taken to travel (d - 60) kilometers upstream is 10 hours. The speed of the current is equal to one-fifth of the boat's speed in downstream conditions. Determine the speed of the boat in still water.Solution
ATQ, Let the speed of the boat in still water be 'U' km/hr and the speed of the current be 'V' km/hr (U + V)/5 = V (U + V)/V = 5/1 U + V = 5p V = p U = 5p – p = 4p km/hr U – V = 4p – p = 3p km/hr 5p × 8 – 3p × 10 = 60 40p – 30p = 60 10p = 60 p = 6 km/hr Speed of the boat in still water = 4 × 6 = 24 km/hr
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
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