Question
The ratio of the distances traveled by a boat in
upstream and downstream is 6:7, respectively, and the total time taken to cover the desired distance is 73 hours. Given that the speed of the current is 40 km/h, which is 8 km/h less than the speed of the boat in still water, determine the distance traveled by the boat upstream.Solution
ATQ, Let the distance covered by the boat in upstream be ‘6a’ km and the distance covered by boat in downstream be ‘7a’ km. Speed of the boat in still water = 40 + 8 = 48 km/h According to question, {(6a/(48 – 40)} + {7a/(48 + 40)} = 73 Or, (6a/8) + (7a/88) = 73 Or, (73a/88) = 73 Or, a = 88 Distance travelled by the boat in upstream = 6a = 528 km
- What will come in place of (?), in the given number series.
1, 4, 9, 16, ?, 36 {(12√5 + 6√5 )} ×{(10√5 - 5√5 )} - 8² + 6² = ?
11          20          ?             64          112        192
...350 435 367 ? 384 401
...0, 6, 24, ?, 120, 210
21, 37, 73, 137, ?, 381
What will come in place of the question mark (?) in the following series?
4, 11, 32, 95, 284, 851, ?
18, 34, 70, 134, ?, 378
120, 136, 111, 147, ?, 162
What will come in place of the question mark (?) in the following number series?
124, 131, 117, ?, 110, 145
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