Question
A boat can travel 200 km downstream in 8 hours and 48 km
upstream in 12 hours. Find the speed of the current.Solution
Let the speed of the boat in still water be 'x' km/hr and the speed of the current be 'y' km/hr. According to the question, 
On solving equations (1) and (2), we add them to get: 2x=29⇒x=14.5 km/hr Then substituting back to find 'y': 25−14.5=y=10.5 km/hr Speed of the current = 10.5 km/hr
63.89% of 549.68 – (739.87 ÷ 5.34) = ? × 11.89
(? + 6.063.03 ) ÷ 10.08 + 21.89 × 6.97 = 1979.97 ÷ 10.96
17.06 2 + √36.08 – (4.04/2.99) × 3.02 × 4.92 = ? × 4.99
20.22% of (74.9 × 6.01) + 69.97 =?
16.98 × 88.05 + 1999.996% of 299.08 + 5.005 % of 4999.997 = ? × 20.98 × 40.009
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
( 22.01% of 899.80 ) × 15.99 = ? 2 + 27.98 × 2400 ÷ 800
11.232 + 29.98% of 599.99 = ? × 6.99
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 599.77 – 14.08 × 20.11 + (12.93)²
63.95 – 21.12 – 24.89 + 6.04 = 3.98 × ? + 3.88
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