The cost price of article ‘A’ is Rs. 4,000 and cost price of article ‘B’ is 125% of that of article ‘A’. If articles ‘A’ and ‘B’ are marked up by 30% and 20% above their respective cost prices and sold after single discounts of 15% and x%, respectively, then there will be a net profit of Rs. 220 on selling these two articles. What is the value of ‘x’?

Cost price of article ‘B’ = 4000 × (125/100) = Rs. 5,000 Marked price of article ‘A’ = Rs. 4000 × 1.30 = Rs. 5,200 Marked price of article ‘B’ = Rs. 5000 × 1.20 = Rs. 6,000 Selling price of article ‘A’ = Rs. 5200 × 0.85 = Rs. 4,420 Let the selling price of article ‘B’ = Rs. ‘K’ Total profit = sum of selling price of articles ‘A’ and ‘B’ – sum of cost price of articles ‘A’ and ‘B’ ATQ, 220 = K + 4420 – 4000 – 5000 Or, (K – 4580) = 220 So, K = 4800 Selling price of article ‘B’ ÷ marked price of article ‘B’ = 4800 ÷ 6000 = 0.80 So, discount given on selling article ‘B’ = (1 – 0.80) × 100 = 20% So, x = 20 Hence, the correct answer is D.