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ATQ; SP of the item = 4000 × (1 - (z + 4)/100) × (1 - (z - 4)/100) = 3328 or, {(100 - z - 4)/100} × {(100 - z + 4)/100} = 3328/4000 or, (96 - z) × (104 - z) = (3328/4000) × 100 × 100 or, 96 × 104 - 96z - 104z + z² = 8308 or, z² - 200z + 9994 - 8308 = 0 or, z² - 200z + 1686 = 0 or, z² - 10z - 190z + 1686 = 0 or, z × (z - 10) - 168 × (z - 10) = 18 or, (z - 10) × (z - 168) = 18 So, z = 10 or z = 168 But, z = 168 is not possible because the discount cannot be more than 100%. Therefore, z = 10
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