Question
A bag contains 8 green balls, 5 yellow balls and 3 blue
balls. Two balls are drawn simultaneously. Find the probability that both the balls are of same colour.Solution
Total number of balls in the bag = 8 + 5 + 3 = 16 Total possible outcomes = 16C2 = 120 Number of favourable outcomes = 8C2 + 5C2 + 3C2 = 28 + 10 + 3 = 41 Required probability = 41/120
More Probability Questions
√3598 × √(230 ) ÷ √102= ?
7(1/2) – 3(5/6) = ? − 2(7/12)
Simplify the following expression.
(3-3 × 3 + 3 ÷ 3 + 3 × 5) × 2 of 5 + (2 + 2 ÷ 2 + 2 × 2 - 2)
What will come in the place of question mark (?) in the given expression?
(437 + ? - 167) x 2.5 = 875I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
?2 = √20.25 × 10 + √16 + 32
15(2/9) + 11(2/9) + 17(1/9) + 13(4/9) = ?
- What will come in the place of question mark (?) in the given expression?
32% of 74% of ? = 16% of 37% of 180 
15% of 695 – 12.5% of 250 =? – 1200
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