8 rotten bananas are accidentally mixed with 110 good ones. It is not possible to just look at a banana and tell whether or not it is rotten. One banana is taken out at random from this lot. Determine the probability that the banana is taken out is a good one.
Numbers of bananas = Numbers of rotten bananas + Numbers of good bananas ∴ Total number of bananas = 110 + 8 = 118 bananas P(E) = (Number of favourable outcomes) / (Total number of outcomes) P(picking a good banana) = 110/118 = 55/59
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