Question
If sinθ +cos θ = √7/2, then find the value of sinθ
– cosθ.Solution
sinθ + cos θ = √7/2, Squaring both sides. ⇒ sin2θ + cos2θ + 2sinθ.cosθ = 7/4 ⇒ 1 + 2sinθ.cosθ = 7/4 ⇒ sinθ.cosθ = 3/8 We can write; sin2θ + cos2θ = (sinθ – cosθ)2 + 2sinθ.cosθ ⇒ (sinθ – cosθ)2 = 1 – 3/4 = 1/4 ⇒ (sinθ – cosθ) = 1/2
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?