Question
In a triangle ABC, the in center is at O. Find angle BAC
if angle BOC=110°.Solution
When the bisector of ∠B and ∠C intersects At the O. Then – ∠BOC =90 ° + ∠A/2 110° =90 + ∠A/2 ∠A/2=20 ° ∠A =20 °×2 =40° ∠A =40° 
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